Biochemistry I Fall Term      Name:

pH Titration:
Given in the problem:
1) Volume of the acid =
2) [NaOH] =
What was found in the experiment:
Vol. NaOH (mL)     pH mequiv.* 
-

-

-

-

-

-

-

-
*Equivalents of NaOH = Volume x concentration.
mequiv. = mL x 1.0 M (i.e. mequiv. = 10-3 x equivalents.)
 
Graph of the calculated results:

The acid concentration =
The pKa =
From Table 2.6 of Campbell, the acid is

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8.20.03