Reading in Campbell: Chapter 2.3-2.6
Key
Terms:
4.1
Solving pH Problems:
The
H&H equation has predictive value.
Once you know the pKa of an acid and the pH, you can predict
[A-]/[HA]. One
particular case is routinely used in biochemistry: Given a pH and pKa
of an acid, calculate the fraction of the acid that is protonated: fHA = ([HA]/AT) and the fraction that is
deprotonated:
fA- = ([A-]/AT),
where AT is the total concentration of acid: AT = [HA] +
[A-].
Defining
R = [A-]/[HA]
pH
= pKa + log([A-]/[HA])
pH
= pKa + log(R)
pH pKa = log(R)
10(pH-pKa)
= R
Once R
is found, the fraction protonated and
deprotonated
is obtained as follows:
[A-]/[HA]
= R
[A-]
= [HA]R
[AT]
= [A-] + [HA]
[AT]
= [HA](1+R)
Using
the ionization of the side chain of the amino acid Histidine as an example (pKa
= 6.0)
pH |
R |
FHA |
4 5 |
R =
10(4-6) = 10-2 R =
10(5-6) = 10-1 |
FHA
= 1/(1+0.01)= 0.99 FHA
= 1/(1+0.1) = 0.91 |
6 |
R =
10(6-6) = 100 |
FHA
= 1/(1+1) = 0.5 |
7 |
R =
10(7-6) = 101 |
FHA
= 1/(1+10) = 0.091 |
8 |
R =
10(8-6) = 101 |
FHA
= 1/(1+100) = 0.01 |
There
are four general statements that are useful to remember:
1.
When
the pH = pKa, [HA] = [A-].
2.
When
the pH is lower than the pKa, [HA]
> [A-].
3.
When
the pH is higher than the pKa, [HA]
< [A-].
4.
A
pH change of 1 leads to a 10 fold change in the ratio of [A-]/[HA].
4.2
Titration Curves
Ka values are usually measured by direct
experiment, usually with a pH titration.
Known amounts of a strong base (NaOH) are added to a solution of a weak
acid and the pH is measured as the amount of NaOH is added. As the base is added it removes the
proton from the acid, as well as increasing the pH.
Inflection
point (pH =
pKa): You can prove from the Henderson-Hasselbalch equation that
the smallest change in pH due to addition of base occurs when the pH = pKa; at this inflection point, the pH of the
solution is the pKa of the acid.
Equivalents: moles of base/moles of acid, the x-axis for titrations. Varies from 0 to 1 for monoprotic
acids.
Equivalence
point: Complete deprotonation of the weak acid
occurs when the molar amount of base is equal to, or equivalent to, the molar
amount of weak acid. This point in
the titration is referred to as the equivalence point.
Example
titration curve:
ml NaOH measured
pH
0.25
3.20
0.5
3.80
1
4.07
2
4.44
3
4.62
4
4.87
5
4.96
6
5.17
7
5.33
8
5.64
9
5.96
10
7.00
(Facts: Concentration of NaOH = 1 M
Volume
of solution that is titrated = 100 ml)
Possible
acids (from Campbell table 2.6)
Pyruvate pKa = 2.5
Acetic
Acid pKa = 4.8
Tris pKa = 8.3
Questions:
1.
What
is the pKa of the acid?
2.
Which
acid is it?
3.
Give
the x-axis scale in equivalents.
4.1
Buffers
A pH buffer is an acid that resists changes in the solution pH by absorbing or releasing protons. Buffers play an important role in cellular processes because they maintain the pH at an optimal level for biological processes. They are also widely used to control pH in laboratory processes.
All
acids function well as buffers for pH values within one pH unit of their pKa value.
Because the pKa of weak acids are near the
physiological pH range, weak acids make good buffers.
Consider
1 L of a 10 mM solution of acetic acid at pH 4.7. At this pH, ~ 50% of the acid is ionized. If 1 mmole of a strong acid (e.g. HCl)
is added, most of the protons that dissociate from the added acid would simply
protonate the acetate ions, reducing their concentration from 5 mM to 4
mM. The resultant pH of the
solution would be:
The
buffering capacity of a weak acid decreases as the dissociation becomes more
complete (if base is added) or as it becomes more protonated (if acid is
added). For example, acetic acid
is a poor buffer at pH 3 or pH 7.
The buffering capacity (ability to absorb protons) depends on both the
concentration of the buffer and the difference between the pH and the pKa.
4.2
Buffer construction
Steps
in making a buffer of concentration [AT]:
1.
Select
a weak acid whose pKa is within one pH unit of the
desired pH.
2.
Calculate
R, based on the difference between the desired pH and the pKa.
3.
Calculate
the required concentration of [HA] and [A-] based on the total
concentration of the buffer ([HA]).
4.
To
obtain this ratio of [HA] to [A-]:
a)
Mix
the indicated concentrations of the acid and its conjugate base to give the
desired pH.
b)
Alternatively,
use [AT] amount of the acid form of the buffer and add
sufficient strong base (e.g. NaOH) to obtain the desired concentration of [A-]
by converting [HA] to [A-] (i.e. the amount of base added equals [A-]).
c)
Alternatively,
use [AT] amount of the conjugate base form of the buffer and add
sufficient strong acid (e.g. HCl) to make the desired concentration of [HA]
(i.e. the amount of acid added equals [HA]).
Or,
instead of performing any calculations whatsoever, use either the conjugate base or the acid form
at a concentration of [AT], and slowly add the strong acid or base,
respectively, until the measured pH is equal to the desired pH. This method of obtaining the desired
buffer solution is most frequently used in practice!
Worked
example:
Make 1L
of a 0.1 M buffer solution at pH 5.0 using one of the following two buffers:
Buffer |
pKa |
MW
(g/m) |
Histidine |
6.0
(side chain) |
200
g/m (155 actual) |
Pyruvic Acid |
2.50 |
100
g/m (88 actual) |
4.3
Polyprotic Acids
·
Many compounds can release more
than one proton
in the pH range of 0-12. Examples are phosphate
(pKa = 2.14, 7.20, 12.40),
carbonate, dicarboxylic acids,
as well as amino acids.
(i.e. phosphoric acid) each
ionization can be treated
separately.
pKa for each ionization can vary widely.
Consider the following examples:
Acid |
pka1 |
pKa2 |
pKa3 |
Phosphoric |
2.14 |
7.20 |
12.40 |
Oxalic |
1.23 |
4.19 |
- |
Why do the pKa
values change after the 1st proton is released?
In what direction do they change (weaker or stronger
acid)?