Structural Test #1:
Analysis of a compression unit
Introduction:
In this
example you will be tested on the 2-D Truss element in ANSYS.
Physical Problem:
The
structure is mainly subjected to loading in the horizontal direction due
to compressive forced. In this example we will consider only loading due
to these forces, which are in the horizontal direction.
Problem
Description:
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The tower is made
up of trusses. You may recall that a truss is a structural element
that experiences loading only in the axial direction. |
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Units: Use S.I.
units ONLY |
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Geometry: the cross
sections of each of the truss members is 6.25e-3 sq. meter.
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Material: Assume
the structure is made of steel with modulus of elasticity E=200 GPa.
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Boundary
conditions: The unit is constrained along X and Y directions at the
bottom right corner and the top left corner. |
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Loading: The tower
is loaded at bottom left corner (6000N). The load on the top right
corner equals -6000N. |
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Objective:
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To determine
deflection at each joint. |
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To determine
reaction forces at the mounted corners. |
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You are required to
hand in print outs for the above. |
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Figure:
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The units are as
explained below, kept simple to expedite the test (all horizontal
and vertical links are 5m long) |
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IMPORTANT:
Convert all
dimensions and forces into SI units. |
·
Create
the keypoints defining the joints for the truss.
·
Connect
them with lines to define the truss links.
·
Define
the Material Properties of the Steel Element (Elastic Modulus and
Poison’s Ration are the important qualities)
·
Define
the Element Properties as a 2D Spar Structural Link
·
Define
the “Real Constants” of the linkage by setting the values for the
Element Type for Real Constants. (Set the values for a Real Constant Set
No. of 1 and a Cross Sectional Area of 6.25e-3)
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Mesh the truss such that each line is exactly one element.
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Apply Boundary Conditions (X and Y movement constraints on the upper
left corner and the lower right corner, on the lower left corner there
is a load of 6000N, on the upper right corner there is a load of
–6000N. |
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Solve |
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List the nodal
results of the analysis. (for both degrees of freedom) |
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Plot the nodal
deformation in the X direction. |
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These are the
results you should expect: |
(The
nodal displacements will be listed as follows)
(The
plot of the deformation will look like this)
